Mole-Mole Conversion Factors

Once it is understood that reaction equations are mole-mole relations, it is possible to use this idea to do stoichiometric calculations. However, to do so the concept of mole-moleconversion factors must be clearly understood. Consider the reaction of chromium(III) hydroxide with sulfuric acid:

We can state relations in this equation both verbally and with a conversion factor in many ways:

Statement

Conversion factor
2 mol of Cr(OH)3 reacts with 3 mol of H2SO4

 2mol Cr(OH)3 3 molH2SO4
2 mol of Cr(OH)3 produces 1 mol of Cr2(SO4)3

 2mol Cr(OH)3 1 mol Cr2(SO4)3
2 mol of Cr(OH)3 produces 6 mol of H2O
 2mol Cr(OH)3 6 mol H2O
3 mol of H2SO4 produces 1 mol of Cr2(SO4)3
 3mol H2SO4 1 mol Cr2(SO4)3
for every 1 mol of Cr2(SO4)3 produced we get 6 mol of H2O
 6mol H2O 1 mol Cr2(SO4)3

Obviously, there are several more relations about this reaction that could be made however, the above should suffice is showing how these mole conversion factors are constructed. We can now use these mole conversion factors to do the stoichiometric calculations.

Back to index
C101 Class Notes
Prof. N. De Leon